Thanks for all the info i will see how I progress at the moment its single track working apart from the station as would be the case of a passing loop as well.
Spa Bahn
- Thread starter FrenchChuffed
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Nice shed!
Deceptive in the picture, how wide it is..
Oh, great progress on the railway as well!
Deceptive in the picture, how wide it is..
Oh, great progress on the railway as well!
Re aligned trackwork to alow better access to the sidings 
Well the shed is 16 feet long i think so only about 22 foot square i thinkNice shed!
Deceptive in the picture, how wide it is..
Oh, great progress on the railway as well!
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I have just taken into storage most of my buildings, as strong winds forecast over the weekend, what do others do to protect there buildings and line side accessories?
I don't - the depot (station) section of my railroad is sheltered by a hedge and my shed - the direction that is open to the garden faces east, and we rarely have extreme winds from the east. The few buildings I have are fixed to the ground
Mine either survive, or not... All are fixed, normally by 4x 4inch screws, which are inside, the inside corners, ie screwed in by 3/4inch..the wind. Would have to lift a building vertical up 4 inches,... The wind blows sideways here..
I will have to see how to fix mine down then, in france they seemed to be more shelters than where i am now. I feel i am in a wind tunnel sometimes.
That will make it 160 square feet floor space. 16 times 10. For cube you would need to multiply that by the height but that gets somewhat tricky as you have the sloping roof to consider. Mathematicians to the fore please?
OK, so let's say the height to eaves is 6ft and the height to ridge is another 2 ft.
I think you could be a bit ambitious with your 10 ft wide, nearer 8ft is my guess.
So, 16 x 8 = 128 sq ft base area, 128 x 6 = 768 cu ft to eaves.
For the gable, the area of a triangle is half base times height, so 6 divided by 2 times 2 = 6 sq ft multiply by the length of 16 to get the volume = 96 cu ft
Add the two, 768 + 96 = 864 cu ft.
So we think the cubic capacity of the shed is 864 cu ft
What do we want to know?
Thanks for the Math. I took his 10ft from his post #89. Of course there are other variables that will reduce the values, internal supports and all that stuff so any calculation will be a nearenoughish and certainly much better than we used to use for project quotes on BR of +/- 10%. These days to get anywhere near that sort of quote to a Public institution on either cost or build time would be a near miracle.OK, so let's say the height to eaves is 6ft and the height to ridge is another 2 ft.
I think you could be a bit ambitious with your 10 ft wide, nearer 8ft is my guess.
So, 16 x 8 = 128 sq ft base area, 128 x 6 = 768 cu ft to eaves.
For the gable, the area of a triangle is half base times height, so 6 divided by 2 times 2 = 6 sq ft multiply by the length of 16 to get the volume = 96 cu ft
Add the two, 768 + 96 = 864 cu ft.
So we think the cubic capacity of the shed is 864 cu ft
What do we want to know?
Oh, OK, missed that.
So you're probably at 1,120 cu ft - but what do you want to do with them all ?
You could certainly fit a lot of Micro Layouts in Document Folders in that space.Oh, OK, missed that.
So you're probably at 1,120 cu ft - but what do you want to do with them all ?
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