Ok this sounds counter intutive.
I have converted one of my digital little ex lgb starter sets already as it had a broken decoder. I have a DC track and battery set up but bought two of these back at the start. They run fine on DC.
I now am to convert the other to battery - DC is to be retained only for visitors as track cleaning is boring!
SO THE QUESTION. If I find the voltage that "tells" the loco chip to go at a nice speed and build a battery to match with a reversing switch and connect it to the track power circuit on the loco (removing pickups etc) Will I effectively still have a digital loco with all it's lights, delayed start etc but running off battery. Or will flicking the switch on suddenly make it go pop?
Also as the voltage drops on a run would it then trigger the loco to gracefully stop, whilst still retaining most of it's charge? Does this mean that it would have very short run times - or does a nimh battery stay constant and die suddenly as oppsed to a linear reduction in volts...
BTW thanks for all the help - one day I will help others when I have the knowledge!
Ian
I have converted one of my digital little ex lgb starter sets already as it had a broken decoder. I have a DC track and battery set up but bought two of these back at the start. They run fine on DC.
I now am to convert the other to battery - DC is to be retained only for visitors as track cleaning is boring!
SO THE QUESTION. If I find the voltage that "tells" the loco chip to go at a nice speed and build a battery to match with a reversing switch and connect it to the track power circuit on the loco (removing pickups etc) Will I effectively still have a digital loco with all it's lights, delayed start etc but running off battery. Or will flicking the switch on suddenly make it go pop?
Also as the voltage drops on a run would it then trigger the loco to gracefully stop, whilst still retaining most of it's charge? Does this mean that it would have very short run times - or does a nimh battery stay constant and die suddenly as oppsed to a linear reduction in volts...
BTW thanks for all the help - one day I will help others when I have the knowledge!
Ian